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💡 Hint: Use x = (–b ± √(b²–4ac)) / 2a to solve any quadratic of the form ax² + bx + c = 0
Question 3 of 10
Solve for x: x² + 5x + 6 = 0. What are the two values of x?
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Hi Irfana! 👋 I'm your AI Tutor. I'm here to help you with Quadratic Equations step by step. Would you like me to explain the formula, walk through an example, or quiz you?
You
Please explain the quadratic formula
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Of course! 🎉
The quadratic formula is:
x = (–b ± √(b²–4ac)) / 2a
Use it when you have: ax² + bx + c = 0
Example: x² + 5x + 6 = 0 → a=1, b=5, c=6
→ x = (–5 ± √(25–24)) / 2 = (–5 ± 1) / 2
→ x = –2 or x = –3 ✅
Want a practice problem?
The quadratic formula is:
x = (–b ± √(b²–4ac)) / 2a
Use it when you have: ax² + bx + c = 0
Example: x² + 5x + 6 = 0 → a=1, b=5, c=6
→ x = (–5 ± √(25–24)) / 2 = (–5 ± 1) / 2
→ x = –2 or x = –3 ✅
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